What is the initial value of the exponential function represented by the table?
a. 1/8
b. 1/4
c. 1/2
d. 1
table
x f(x)
-2 1/8
-1 1/4
0 1/2
1 1
2 2

Explanation:

We know that the initial value of a function is the output of the function when the input is zero.

In other words, it is the value of f(x) when x = 0

Now, checking the given table, we can find that:

at x = 0 ...............> f(x) =

This means that the output is when the input is zero which means that our initial value is

Hope this helps :)

C. 1/2

Step-by-step explanation:

This is the quick answer, for a full explanation see the above answer. Hope this helped.

i think is g(1)=-1.

hope that i can

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)