The graph of the function y=x^2-x-2 is shown below

Option D is correct

Step-by-step explanation:

A quadratic equation is in the form of   ....[1]

then;

the axis of symmetry is given by:

Vertex =

As per the statement:

Given the function:

       ....[2]

On comparing with [1] we have;

a = 1, b = -1 and c = -2

Then;

Substitute the value of x in f(x) we have;

⇒

Vertex =

x-intercept states that the graph crosses the x-axis.

From the graph, the function cuts the x-axis at:

x = -1 and x = 2

x-intercepts = (-1, 0) and (2, 0)

y-intercept states that the graph crosses the y-axis

From the given graph we have;

y = -2

y-intercept = (0, -2)

Therefore,

Vertex =

Axis of symmetry:

x-intercepts = (-1, 0) and (2, 0)

y-intercept = (0, -2)

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is