the loudest sound measured one night during a hockey game was 112 db. the loudest sound measured during a hockey game the next night was 118 db. what fraction of sound intensity of the second game was the sound intensity of the first game?

To determine the fraction that the sound intensity of the first game by the second game, we divide the lowest sound on the second night by the sound intensity of the first game and multiply the answer by 100%.
                                    % = (112/118)  x 100%
                                       = 94.915%
Thus, the intensity of the first round is approximately 94.915% of the second. 

It'll be 14/21, 8/12, and 10/15.14/21=2/312/16=3/48/12=2/310/15=2/3