Mathematics, 01.01.2020 02:31 mitetwojr

If a rectangle has a greater perimeter than another rectangle, does it also have a greater area? explain.

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No.

The maximum possible area given a constant amount of material for a quadrilateral will always be a square.

For example if the material for the perimeter is 64 we can form a rectangle that is 22 by 10 which will have an area of 220 u^2.

However a square using the same amount of material will have sides of 64/4=16 and an area of 16^2=250 u^2

So in general the area is maximize the closer the sides are to being equal and minimized as the difference between the sides becomes greater. In the case of comparing the material, perimeter, of a rectangle to a square for the same amount of material the square will use less material than the rectangle.

A square can have a smaller perimeter and a greater area that a rectangle.

In the example above the rectangle had a perimeter of 64 u and an area of 220 u^2. If we made a square with just 60 u, it would have an area of 225 u^2.

Answer from: Quest

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2 polynomial long division

dividing : x4+5x3-4x2-8x+6

("dividend")

by : x-1 ("divisor")

dividend x4 + 5x3 - 4x2 - 8x + 6

- divisor * x3 x4 - x3

remainder 6x3 - 4x2 - 8x + 6

- divisor * 6x2 6x3 - 6x2

remainder 2x2 - 8x + 6

- divisor * 2x1 2x2 - 2x

remainder - 6x + 6

- divisor * -6x0 - 6x + 6

remainder 0

quotient : x3+6x2+2x-6 remainder: 0

Answer from: Quest

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

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If a rectangle has a greater perimeter than another rectangle, does it also have a greater area? ex...