Suppose an investment of $6,200 doubles in value every 13 years. how much is the investment worth after 78 years?

$396,800

Step-by-step explanation:

Given: The initial investment = $6200

The constant ratio = 2

Time takes to double the amount (Time period )= 13

The number of time periods in 78 years =

The exponential growth equation is given by :-

, whre A is the initial amount , b is the constant ratio and x is the number of time periods .

Now, the investment worth after 78 years will be given by :-

Hence, The  investment worth after 78 years is $396,800.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.