What are the removable discontinuities of the following function?
f(x)=x^2-36/x^3-36x

Factoring  f(x)  = (x - 6)(x + 6)
                         
                           x(x - 6)^x + 6)

the removable discontinuities are  when x = 6 and when x = -6

the removal discontinuity of the following function at x=-6 or x=6.

Step-by-step explanation:

Since discontinuity are at x=0 ,6 or -6.

After cancelling, it leaves you with for x≠0.

Therefore, x+6=0(or x=-6) , x-6=0(or x=6)  is a removal discontinuity of the following function.

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%