Mathematics, 28.09.2019 00:00 nicko10
How to find the average squared distance between the points of the unit disk and the point (1,1)
Answers: 1
and 
. The squared distance between any point in this region 
and the point (1, 1) is
![=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}](/tpl/images/0269/5068/75e66.png)
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