Arectangular section of a wall in a library is 90 in. long and 72 in. wide. a librarian is hanging photos on this section of the wall. each photo needs a space of approximately 8 in. by 10 in.
which estimate best approximates the number of photos that can be hung on the section of the wall?
a. 80
b. 160
c. 650
d. 810

A. 80

Step-by-step explanation:

Length of rectangular section of a wall = 90 inches

Width of rectangular section of a wall = 72 inches

Area of rectangular section of a wall =

                                                             =

                                                             =

Each photo needs a space of approximately 8 in. by 10 in.

So, area of each photo =

                                       =

                                       =

Now he number of photos that can be hung on the section of the wall:

So, 80  estimate best approximates the number of photos that can be hung on the section of the wall.

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.