Clair has 60 yd of fence with which to build a rectangular pig sty. what is the maximum area she can enclose?

Assuming this Fence enclosment will be in the shape of a rectangle we will use the equation used to find the area of a rectangle, b×h=a

Using this formula we then must pick out factors used to create, in which the perimeter will add up to 60

·1,29,1,29 (29)
·2,28,2,28 (56)
·3,27,3,27 (81)
·4,26,4,26 (104)
·5,25,5,25 (125)
·6,24,6,24 (144)
·7,23,7,23 (161)
·8,22,8,22 (176)
·9,21,9,21 (189)
·10,20,10,20 (200)
·11,19,11,19 (209)
·12,18,12,18 (216)
·13,17,13,17 (221)
·14,16,14,16 (224)
·15,15,15,15 (225)

using this we can learn that the maximum area that can be exclosed by this is 225, because the 2 perimeter lengths that define this rectangle would be 15 and 15.

b(15)×h(15)=225(a)

therefore, your answer is 225 Units

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