Anita’s sister invested all of $6000 at 4% and at 6%. if the annual return on the 6% investment is $15 more than the annual return on the 4% investment, find how much is invested at the latter rate.

$3,450

Step-by-step explanation:

The amount invested in the two portfolios sums up to $6,000. Given that the  annual return on the 6% investment is $15 more than the annual return on the 4% investment, then if the annual return on the 4% investment is I, the returns on the 6% investment will be

= I + 15 (in $)

the return on investment may be computed using the simple interest formula

I = PRT/100

Where I is the return, P is the amount invested, R is the rate of returns and T is time in years.

let the amount invested in the 4% investment be D, then the amount invested in the other will be

= 6000 - D

Considering the two investments

I =  D * 4 * 1/100

100I = 4D

D = 25I

I + 15 = (6000 - D) * 6 * 1/100

100I + 1500 = 36000 - 6D

100I + 6D = 34500

4D + 6D = 34500

10D = 34500

D = $3,450

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x