Let an integer be chosen at random from the integers 1 to 30 inclusive. find the probability that the integer chosen is divisible by 4 or is greater than 25 and less than 30.

Hence, the required probability is:

                    1/3

Let A denote the event that the integer chosen is divisible by 4.

i.e. A={4,8,12,16,20,24,28}

Hence, P(A)=7/30

and B denote the event that the integer is greater than 25 and is less than 30.

i.e. B={26,27,28,29}

Hence, P(B)=4/30

Hence, A∩B denote the event that the integer us divisible by 4 and is greater than 25 and is less than 30.

i.e. A∩B={28}

Hence, P(A∩B)=1/30

and A∪B denote the event  that the integer chosen is divisible by 4 or is greater than 25 and less than 30.

Hence,we know that:

                  P(A∪B)=P(A)+P(B)-P(A∩B)

i.e.    P(A∪B)=7/30+4/30-1/30

        P(A∪B)=10/30

        P(A∪B)=1/3

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

3030 ur welcome

step-by-step explanation: