![[3x(x+4)7x]](/tpl/images/0463/9534/2f877.png)
both sides![\frac{3[3x(x+4)7x]}{3x}+\frac{[3x(x+4)7x]}{x+4}=\frac{10[3x(x+4)7x]}{7x}](/tpl/images/0463/9534/a660b.png)
![3[(x+4)7x]+[3x(7x)]=10[3x(x+4)]](/tpl/images/0463/9534/53e14.png)
both sides
is equal to
Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x .
x = −3
x = 3<...
Mathematics, 21.01.2020 09:31 edjiejwi
Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x .
x = −3
x = 3
x = −3 and x = 3
no solution
Answers: 2
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