The scores on a certain test are normally distributed with a mean score of 43 and a standard deviation of 3. what is the probability that a sample of 90 students will have a mean score of at least 43.3162?
0.8413
0.3174
0.1587
0.3413

0.1587

Step-by-step explanation:

Given: Mean :

Standard deviation :

Sample size : n = 90

We know that , the value of z is given by :-

For x=4.2

The p value =

Hence, the probability that a sample of 90 students will have a mean score of at least 43.3162= 0.1587

the correct answer is 828.07