Find the distance between points p(2,2) q(7,4) to the nearest tenth

If you know the horizontal distances between the two points is a positive 5, and the vertical distance is a positive 2. By using the distance formula, you can come up with sqrt(5^2+2^2) = 5.38516480713, which to the nearest tenth would be 5.4

Distance formula srqt( (x2-x1)^2 + (y2-y1)^2 )
sqrt((7-2)^2 +(4-2)^2)
sqrt ( 5^2 + 2^2)
sqrt ( 25 + 4)
sqrt (29)
= 5.4