Arthur drops a ball from a height of 81 feet above the ground. its height, h, is given by the equation h = –16t^2 + 81, where t is the time in seconds. for which interval of time is the height of the ball less than 17 feet?

Step-by-step explanation:

Arthur drops a ball from a height of 81 feet above the ground. Its height as a function of time is given by :

...........(1)

Where

t is in seconds

We need to find the time interval when the height of the ball is less than 17 feets. Equation (1) becomes :

When the time is more than 2 seconds, the height of the ball is less than 17 feet. Hence, this is the required solution.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure