What is the final balance for an account starting with $2000 at 3.5% interest compounded annually for 3 years? a = p(1 + r)t a. $2217.44 b. $4290.75 c. $6210.00 d. $8100.00

I know this is late, but I can help explain so you can understand it.

Use this:  A = P(1 + r)t

So,  

P = 2,000 (How much you starting off)

r  = 3.5% or 0.035 (your interest)

t =  3 (years)

The formula looks like this: 2000(1 + 0.035)^3

                                            2000(1.035)^3

                                            2000 x 1.1087...

                                           =  2217.44

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12