Regular pentago abcde has a side length of 6square root of 5 cm & area of 309.7 cm square & regular pentagon qrstu has a side length of 8cm & perimeter of 40cm. find the perimeter of pentagon abcde & area of pentagon qrstu

Both are regular pentagons, so each have 5 equal sides

now, the ABCDE one, has sides with length of 6√(5), well the perimeter of any shape, is all its sides or its borders, added up, so, 5 sides, each 6√(5), then the perimeter of ABCDE is 6√(5)+6√(5)+6√(5)+6√(5)+6√(5) or 5[ 6√(5) ]

now to get the area of pentagon QRSTU, we know it has 5 sides, and each side is 8cm in length

thus   

now, the angle there is in degrees, thus, make sure your calculator is in Degree mode

The answer to the question is d

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