What is the probability that a point chosen at random in the given figure will be inside the smaller circle? enter your answer, as a fraction in simplest form, in the box. p(inside smaller circle) = ? $\text{basic}$basicbasic 789÷divided by456×multiplied by123-0.,+plusleftrightbackspace=eq uals $x$x$y$y$x^2$x2$\sqrt{ }$√$\frac{x}{ }$ x $x\frac{ }{ }$x $x^{ }$x$x_{ }$x< > ±$%$\degree$°: $\left(\right)$()$\abs{ }$$\pi$π$\infty$∞ a circle with a radius of 4 centimeters is within a larger circle with a radius of 10 centimeters. both circles share the same center.

the image of (6, 9) under a dilation is (4, 6). the scale factor is

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !