Write (3i - 2/3) - (6i-5) as a complex number in standard form. i have no idea what im doing to be honest give me pointers or hints or anything to me get this done . : )

so, the standard form is:  

Step-by-step explanation

The standard form of a complex number is given in the form of:

where a,b belongs to real numbers.

we are given the expression in complex number as:

on combining the like terms i.e. on combining the real and imaginary part of the complex number we get,

Hence, on comparing our number with the standard form of the complex number we get

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer: y=4000x+14000

step-by-step explanation: