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Mathematics, 30.10.2019 09:31 PersonPerson13260

(8.02 lc)

solve 6/x-6 = x/x-6 - 6/2 for x and determine if the solution is extraneous or not.

a. x = −6, extraneous

b. x = −6, non-extraneous

c . x = 6, non-extraneous

d. x = 6, extraneous

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(8.02 lc)

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