Evaluate the surface integral. s x2z2 ds s is the part of the cone z2 = x2 + y2 that lies between the planes z = 4 and z = 5

The value of the given surface integral is 3843/ and this can be determined by doing the integration.

Given :

S is the part of the cone z2 = x2 + y2 that lies between the planes z = 4 and z = 5.

First, parameterize S as given below:

In the above expression the value of and .

Now, evaluate the surface integral as given below:

Simplify the above integration in order to get the value of the surface integral.

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you first to choose the points and then move from then as the slope you have