Solve this simultaneous equation! step by step

1:       2x+y=3
         5x-2y=12

2:      Multiply the first equation by 2
         (2) (2x+y=3) => 4x+2y=6

3:      Add
         4x+2y=6
    +   5x-2y=12

         9x=18               The y's cancel out
         9x/9=18/9         The 9's cancel out
         x=2

4:     Plug (x=2) back into either equation but, I'm going to do the first one. It's  easier.
         2(2)+y=3
             4+y=3
          4-4+y=3-4         The 4's cancel out
                y=-1
(12,-1)
If you plug (x) and (y) back in it will equal 3 for the first and 12 for the second.