Regular pentagon qrstu has a side length of 12 cm and an area of about 248 square cm. regular pentagon vwxyz has a perimeter of 140 cm. find the area of vwxyz. round to the nearest tenth. a. 578.7 square cm b. 912.4 square cm c. 1,350.2 square cm d. 2,893.3 square cm

answer: 4 (:

step-by-step explanation:

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.