Signal mistakenly produced 1,000 defective cell phones. the phones cost $60 each to produce. a salvage company will buy the defective phones as they are for $30 each. it would cost signal $80 per phone to rework the phones. if the phones are reworked, signal could sell them for $120 each. assume there is no opportunity cost associated with reworking the phones. compute the incremental net income from reworking the phones.

Number of defective cell phone produced = 1000.

Defective phones cost $30 each.

Cost of defective phones =30x1000=30,000.

Cost of producing 1000 cell phones = 60x1000=$60,000.

Cost of rework= 80x1000=80,000.

Rework phone sale value =120x1000=120,000.

Incremental net income = 120,000-80,000-30,000= $10,000.

The  incremental net income from reworking the phones is $10,000.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.