The pyramid shown has a square base that is 12 centimeters on each side. the slant height is 18 centimeters. what is the surface area of the pyramid?

The surface area of the pyramid is 576.

The square base is 144. It's just a square, so you multiply 12 (length) and 12 ( width) , which equals 144.

Then you find the area of one of the triangles. The equation to find triangles goes like this: 0.5 x B (base: 12) x H (height: 18). That would be 6 x 18 which is 108.

Since you got the area of 1 triangle and there are 4 triangles you have to multiply 108 by 4. That'll give you 432.

SO since you have the area of all the triangles and the square base the last thing you have to do is just add it all up.

The area of the triangles plus the area of the square base = the surface area.

432 cm + 144 cm =576 cm.

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -