Δabc is an isosceles triangle with ab = bc= 6 units. d and e are the midpoints or ab and bc, respectively. the length of ac is 8 units. the length of de is units

here are two triangles that exist in this problem. First is the given triangle ABC, witch AB = BC = 6 and AC = 8

Next is the smaller triangle formed by connecting points D and E; triangle EAD, with EA = AD = 3 and the length of DE is unknown.

Because these triangles are similar, a simple ratio may be set up in order to calculate DE.

DE / AC = EA / AB

DE = 3/6 * 8

DE = 4 units

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Step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

11

step-by-step explanation:

32.50-7.50=25

225/25=11