The depreciating value of a semi-truck can be modeled by y = ao(0.85)x, where y is the remaining value of the semi, x is the time in years, and it depreciates at 15% per year.
what is the value of the truck initially, ao, and how would the graph change if the initial value was only $65,000?
$70,000, and the graph would have a y-intercept at 10,000
$75,000, and the graph would have a y-intercept at 65,000
$75,000, and the graph would fall at a slower rate to the right
$75,000, and the graph would fall at a faster rate to the right

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.