Find the area of the region bounded by the curves y = 2x2 and y =4+ x

F(x) =2x² & g(x)=4+ x

1) let's find their points of intersection
f(x) =g(x) ==>  2x² =4+ x  & x' =1/4 + √(33) /4 & x" =1/4 - √(33) /4
x' being the upper limit & x" the lower limit

2) to find the area you will set Area = ∫2x².dx  - ∫4+x)dx
3) ===> (2x³)/3 + c- (x²+ 4x) -c
4) Calculate the area : ∫2x².dx  - ∫4+x)dx = (2x³)/3 - x²- 4x
5) Replace x by the upper value of x & subtract by replacing x in the lower value.
Use your calculator to find the Area
 

The answer would be b ! explanation: the formula for sa *surface area * is 2×l×w+2×l×h+2×w×h so in this case l=4w=12h=8so you use the formula to solve it and it give you the answer of 352^cm^2

For 1, d is your answer