Factorise p^2-6p+5,, my minds gone blank i've forgot which way round the finding numbers that x& + to make 6,5 in this case : )

P^2-6p+5

To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions:

jk=ac=5 and j+k=b=-6, so j and k must be -1 and -5

now replace bx with jx and kx in the original equation to get:

p^2-p-5p+5 and then factor 1st and 2nd pair of terms...

p(p-1)-5(p-1)

(p-5)(p-1)