Find an equation of a line through (2, 1) and perpendicular to −2x + 4y = 8
a. y = −2x − 3
b. y = −2x + 3
c. y = −2x + 5
d. y = −2x − 1

Hello:
the equation is : y = ax+b
the slope is a : a×(1/2) = -1( perpendicular to a line with a slope of   1/2)            because :    -2x+4y =8...y=(1/2)x+2    )     

a = -2       y=(-2x+b
the line that passes through (2,1) :1 = -2(2)+b
b =5
 the equation is :  y  = -2x+5

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.