Identify the equation or coordinates of the following conic and its equation.

find the equations for the asymptotes of the hyperbola

x^2/16 - y^2/9 = 1

ANSWER:

Since your hyperbola has the "x" term listed first, it opens "right and left.'

It's also centered at (0,0)

So the form is: x²/a² - y²/b² = 1

In your case,

a² = 16,

so, a = √(16) = 4.

And b² = 9,

so, b = √(9) = 3.

So, the equations for the asymptotes are y = +(b/a)x and y = -(b/a)x

So we have, in your case

y = +(3/4)x and y = -(3/4)x.

5 pm

step-by-step explanation:

answer: it's upside down and i can't read it

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