The equation of line lm is y = 5x + 4. write an equation of a line perpendicular to line lm in slope-intercept form that contains point (−3, 2).

Hello:
the equation is : y = ax+b
the slope is a : a×(5) = -1( perpendicular to a line with a slope of   5)         

a = -1/5         y=(-1/5)x+b
the line that passes through (-3, 2)  2 = (-1/5)(-3)+b
b =7/5
 the equation is :  y  = (-1/5)x+7/5

child does not get an education so she can use the molla on junk

17.08

correct me if i am wrong.