Team x and team y have a tug of war. from their starting positions team x pulls team y forward 3 meters, and team x is then pulled forward 5 meters. team y then pulls team x forward 2 meters. if the first team to be pulled forward 10 meters loses, how many more meters must team y pull team x forward to win?

 In any tug-o-war that I have participated in, the losing team has to be pulled a certain distance forward FROM THE STARTING POINT. 

If that is the case in this instance, then 

a) team X pulls Y forward 3m, therefore X's position is X - 3. 

b) team Y pulls X forward 5m, therefore X's position is now X - 3 + 5 

c) team Y pulls X forward another 2m, therefor X's position is X - 3 + 5 + 2 = X + 4. 

That means that X is 4m in front of the starting position. So they must be pulled another 6m if Y is to win.