Y=-3x+9
y=-x-5

what is the solution for the system of equations?

Our system of equations is:

y = -3x + 9

y = -x - 5

To solve this system of equations, we are going to use substitution. This means that we are going to substitute the second equation into the first equation since both are already solved for y in terms of x.

y = -3x + 9

-x - 5 = -3x + 9

Now, we must simplify by moving all of the constant terms to one side of the equation and all of the variable terms to the other side.

-x - 5 = -3x + 9

2x - 5 = 9

2x = 14

Finally, to undo the multiplication between the coefficient 2 and the variable x, we must divide both sides by 2 to get the variable x alone.

x = 7

Next, we must substitute in this value we have solved for x into one of the original equations to solve for the other variable, y.

y = -3x + 9

y = -3(7) + 9

To simplify, we must multiply through the parentheses and combine like terms by addition.

y = -21 + 9

y = -12

Therefore, your final answer is x = 7 and y = -12, or as an ordered pair (7, -12).

Hope this helps!

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b