The pheasant population on an island is declining at a rate of 1.7%per year. the population was 4600 in the year 2009.what is the best prediction of the population in the year 2015

4150 pheasants in the year 2105

Step-by-step explanation:

First thing we are going to do is define the years.  We will call year 2009 our year t = 0.  Therefore, year 2015 is t = 6.

The decay equation that we need has a standard form of

where P(t) is the ending population after a certain amount of time goes by, a is the initial population at t = 0, r is the rate in decimal form, and t is time in years.  Fitting in our info gives us a standard form equation that looks like this:

This means that we are looking for the ending population at a rate of decay of 1.7% after 6 years have gone by.

Doing the subtraction in the parenthesis first simplifies it down a bit to

Raise .983 to the 6th power to get

P(t) = 4600(.9022379843)

and then multiply to get

P(t) = 4150

This means that in the year 2015 the population of pheasants is 4150, dropping from 4600 six years earlier.

the first one, all those points on the line just make a strait line.

answer: the correct answer is -32

step-by-step explanation: