Efgh is a rhombus. given eg = 16 and fh = 12, what is the length of one side of the rhombus?

Answer

= 10

Explanation

EG is one of the diagonals of the rhombus and the other diagonal is FH.

EG = 16 and FH = 12

The diagonals of a rhombus meet at 90°

From this information we can form a right triangle with legs (16/2)=8 and (12/2)=6

The hypotenuse of this triangle is the side of the rhombus.

Using the pythagorean theorem;

L² = 6²+8²

Where L is the length of the rhombus.

L² = 6²+8²

L = √36+64

= √100

= 10

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are