If a polynomial function f(x) has roots 3 and square root of 7 what must also be a root of f(x)?
a negative square root of 7
b i square root of seven
c –3
d 3i

A is correct.

Step-by-step explanation:

A polynomial function f(x) has root .

3 is a real number.

is an irrational number.

The zeros or root of the function always occurs in conjugate pair.

Conjugate pair: A root has two form one positive and one negative.

e.g:

For the given function f(x), should be in conjugate pair.

One more possible root would be

Hence, the one root must be negative of root of 7

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a