What can you say about the end behavior of the function f(x)=log2(4x+8)+16
one end increases and one end decreases
both ends increase
both ends decrease
or one end decreases and one end approaches a constant

One end increases and one end decreases because log2=0.3 and if you multiply that by the leading coefficient, 4, you will get 1.2. Because the new leading coefficient, 1.2, is positive, one end goes up and another end goes down. 

Welp life just is hard