Which polynomial will definitely have nonreal zeros?
hint: use descartes's rule of signs.

x3 − 2x2 − x − 2

x3 − 2x2 + x − 2

x4 + 8x2 + 16

x4 − 8x2 + 16

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

2nd one in the first row is correct

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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the answer is 8/21

hope this