Best gets brainliest! find the perimeter and area of each polygon. show steps!

Perimiter is just the length around
something fun is if all the angles are right angles, then the perimiter is... confusing, I'll explain later

area=length times width for rectangles and 1/2base times heigt for triangles

easiest way to find area is to find the area of 2 shapes

8.
see, all right angles
if we 'pushed' the y side to the right and the 21 side down, we get 1 single rectangle with length 55 and width 43, so then perimiter=2(55+43)=196ft
the area, is
hmm, cut into 2 rectangles
55 by 15 and y by x
x=55-21=34
y=43-15=28

area=55*15+34*28=1777 squar feet

9., just add them up
to get
21 and 3/4ft=perimiter

area
cut into 2 triangles
or use trapezoid
base1=7 and 3/8
base2 is 2 and 1/8
height=5
area=(1/2)h(b1+b2)
so area=(5/2)(19/2)=23/2=11 and 1/2 square feet

11. push x left and 1 and 3/8 up
it is 3 and 1/2 by 2 and 1/4
so perimiter=2(3 and 1/2+2 and 1/4)=11 and 1/2 inches

area
it is 1 and 3/8 by 1 and the 2nd one is y by 2 and 1/4
y=3 and 1/2-1 and 3/8=2 and 1/8

area=197/32 square inches or6 and 5/32 square inches

The answer is: a = about 63.59ft2 for 15