What values of a and b make the equation true? sqrt(648)=sqrt(2^a•3^b)
a) a=3, b=2
b) a=2, b=3
c) a=3, b=4
d) a=4, b=3

ANSWER

The value of a and b are:



EXPLANATION

The expression given to us is



We square both sides of the equation to obtain



We now find the prime factorization of 648 to obtain,



We now compare the exponents on both sides of the equation to obtain,



Therefore the correct option is C

The answer would be 484