What two numbers have a difference of 5 and a product of 3.36

X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula

for
ay^2+by+c=0

for 1y^2+5y-3.36




y=-2.5+/-3.1
y=5.6 or 0.6
sub back

x=y+5
so
x=10.6 or 5.6

the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer

answer is 0.6 and 5.6

Iwish i knew the answer but i don’t but someone will come and us