There are three red marbles, four white marbles, five yellow marbles, and six black marbles in a bag. what is the probability of drawing two red marbles, if you don't replace the marble after you draw the first one? 1/51 1/6 1/36 1/54

Step-by-step explanation:

Given,

Red marbles = 3,

White marbles = 4,

Yellow marbles = 5,

Black marbles = 6,

Total marbles = 3 + 4 + 5 + 6 = 18,

So,

Now, Here, replacement is not allowed,

Remaining red marbles = 3 - 1 = 2,

Remaining total marbles = 18 - 1 = 17,

So,

Hence, the probability of drawing two red marbles = The probability of red marble in first drawn × The probability of red marble in second drawn

First option is correct.

13

step-by-step explanation:

divide the cost of the total of sodas you bought by the cost of one soda, for example:

$24.57 divided by $1.89 is 13 which means you bought 13 sodas