The equation of a linear function in point-slope form is y – y1 = m(x – x1). harold correctly wrote the equation y = 3(x – 7) using a point and the slope. which point did harold use?

when harold wrote his equation, the point he used was (7, 3).
when harold wrote his equation, the point he used was (0, 7).
when harold wrote his equation, the point he used was (7, 0).
when harold wrote his equation, the point he used was (3, 7).

When Harold wrote his equation, the point he used was (7,0).

Step-by-step explanation:

The equation of a linear function in point-slope form :

 --A

Where m is the slope

are passing points

Harold's Equation :

On comparing Harold's Equation with A

Thus the passing point is (7,0).

Hence Option C is correct.

When Harold wrote his equation, the point he used was (7,0).

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

question:

could we have options?