Asand box has an area of 45 ft. the length is 4 feet longer than the width. what are the dimensions of the sand box? solve by completing the square

So,

The sand box's area is 45 ft.

The length is 4 feet longer than the width.

We can solve by translating these sentences into mathematical form.

Let l represent length and w represent width.

First equation: lw = 45

Second equation: l = 4 + w

Substitute 4 + w for l in the first equation.
(4 + w)w = 45

Distribute


Subtract 45 from both sides


Factor


Set both factors equal to zero.
w + 9 = 0
w - 5 = 0

Subtract 9 from both sides
w = -9

Add 5 to both sides
w = 5

We have to cross out -9 for the width, because, logically, it is impossible to have a negative width.

Substitute 5 for w in the second original equation.
l = 4 + (5)
l = 9

Check
5 * 9 = 45
45 = 45 This checks.

9 = 4 + 5
9 = 9 This also checks.

The length is 9 ft. and the width is 4 ft.

This polygon has 4 sides
180(4-2) = 180(2) = 360 degree
80+90+2x + 3x = 360
170+5x = 360
5x = 190
x= 38
measure of angle t is 2(38)= 76
the answer is c. trust me
hope this !