Aregular hexagon with sides of 3" is inscribed in a circle. find the area of a segment formed by a side of the hexagon and circle. (hint: remember corollary 1-- the area of an equilateral triangle is 1/4(s^2)(sqrt

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

it's a proportional graph.

step-by-step explanation:

8 x 5 = 40         (and you have -8x and -5y)

x= absiss

y= orderly

so you have a proportional graph.