If y=x-6 were changed to y=x+8, how would the graph of the new function compare with the first one

The equation  passing through the points (6,0) and (0,-6) but the equation passing through the points (-8,0) and (0,8).

Step-by-step explanation:

We are given that

change into

We have to tell how the graph changed.

(equation I)

Substitute x=0 then we get

When substitute y=0 then , we get

The equation y=x-6 cut the x- axis at x=6 and y- axis at y=-6.

(equation II)

Substitute x=0 then, we get

Substitute y=0 then, we get

The equation cut the x- axis at x=-8 and y- axis at x=8.

The equation  passing through the points (6,0) and (0,-6) but the equation passing through the points (-8,0) and (0,8).

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation: