Write the simplest form and identify the non-permissible values.
4(x squared-9)squared-(x+3)squared/x squared+6x+9

+ 6x + 9} =\frac{4(x^{4} - 9x^{2} - 9x^{2} + 81) - (x^{2} + 3x + 3x + 9)}{x^{2} + 6x + 9} =\frac{4(x^{4} - 18x^{2} + 81) - (x^{2} + 6x + 9)}{x^{2} + 6x + 9} = \frac{4x^{4} - 72x^{2} + 324 - (x^{2} + 6x + 9)}{x^{2} + 6x + 9} =\frac{4x^{4} - 72x^{2} - x^{2} + 6x + 324 + 9}{x^{2} + 6x + 9} =\frac{4x^{4} - 73x^{2} + 6x + 333}{x^{2} + 6x + 9} = 4x^{2} - 24x + 35 + \frac{12x + 18}{x^{2} + 6x + 9}[/tex]

Answer:

$4034.40

step-by-step explanation:

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40