Alock has four dials. on each dial are the digits 0-9. how many possible combinations are there?

There are 6561 posible combinations.

Step-by-step explanation:

the lock has four dials.

And we know that the first dial has 9 posible numbers (0, 1, ... , 9)

the second dial also has 9 posible numbers, and it is the same for the other two.

The total number of combinations is the product of the posibilities for each dial:

c = 9*9*9*9 = 9^4 = 6561

answer: c i think

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b