In triangle xyz, m∠z > m∠x + m∠y. which must be true about △xyz?

m∠x + m∠z < 90°

m∠y > 90°

∠x and∠y are complementary

m∠x + m∠y < 90°

D)m∠X + m∠Y < 90°

Step-by-step explanation:

Given: In triangle XYZ, m∠Z > m∠X + m∠Y.

In a triangle the sum of the interior angles is 180 degrees.

m∠Z is greater than the sum of the angles X and Y.

Two angles cannot be equal to or greater than 90 degrees because the sum of the angles exceeds 180 degrees.

Therefore, the sum of the angles X and Y must be less 90 degrees.

So, answer is D)m∠X + m∠Y < 90°

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